Bhavana V

Parabola Graph

Equation: f(x)= -x^2
Domanin: (- inifinity, + inifinity)
Range: [0, + infinity)
Symmetry: - (-x)^2
=-x^2
Yes, symmetric
Even: Yes (show work)

End behavior (using limits)

f(x) = -x^2
x-> 0^+
= - infinity
f(x)= -x^2
x-> 0^-
= - infinity
f(x)= - infinity
x-> 0

f(x)= - infinity
x-> infinity
f(x)= - infinity
x-> - infinity

Hence f(x) in this case, forever continues to - infinity, therefore it has NO discontinuities.